I’m insecure

生活的戏剧化让人惊诧。我不知道自己是应该笑还是哭。疯了。

我看着它被巨大的校巴碾过,我就这样看着它发生…

神奇…很多东西就是这样说不在就不在的…人也是…

这个世界就是这样让我感到不安。

Enjoy the dramatic part.

Rest in peace, my mobile 2.

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5 条 I’m insecure 的回复

  1. Julie says:

    好好珍惜拥有的东西,已经足够!

  2. Zhikan says:

    最近喜欢上了一样东西,魂牵梦绕…
    这就是python~~一个字,美…
    管他交大上没上,我就沉在我喜欢的事情里,不管别的…
    至于简历,再议了,我就不信找不到工作…
    贴一下google的pageranking的python版
     
    #!/usr/bin/env python
    from numpy import *
    def pageRankGenerator( At = [array((), int32)],  numLinks = array((), int32),   ln = array((), int32), alpha = 0.85,  convergence = 0.01,  checkSteps = 10 ): """ Compute an approximate page rank vector of N pages to within some convergence factor. @param At a sparse square matrix with N rows. At[ii] contains the indices of pages jj linking to ii. @param numLinks iNumLinks[ii] is the number of links going out from ii.  @param ln contains the indices of pages without links @param alpha a value between 0 and 1. Determines the relative importance of "stochastic" links. @param convergence a relative convergence criterion. smaller means better, but more expensive. @param checkSteps check for convergence after so many steps """
     # the number of "pages" N = len(At)
     # the number of "pages without links" M = ln.shape[0]
     # initialize: single-precision should be good enough iNew = ones((N,), float32) / N iOld = ones((N,), float32) / N
     done = False while not done:
      # normalize every now and then for numerical stability  iNew /= sum(iNew)   for step in range(checkSteps):
       # swap arrays   iOld, iNew = iNew, iOld
       # an element in the 1 x I vector.    # all elements are identical.   oneIv = (1 – alpha) * sum(iOld) / N
       # an element of the A x I vector.   # all elements are identical.   oneAv = 0.0   if M > 0:    oneAv = alpha * sum(iOld.take(ln, axis = 0)) * M / N     # the elements of the H x I multiplication   ii = 0    while ii < N:    page = At[ii]    h = 0    if page.shape[0]:     h = alpha * dot(      iOld.take(page, axis = 0),      1. / numLinks.take(page, axis = 0)      )    iNew[ii] = h + oneAv + oneIv    ii += 1    diff = iNew – iOld  done = (sqrt(dot(diff, diff)) / N < convergence)    yield iNew
    def transposeLinkMatrix( outGoingLinks = [[]] ): """ Transpose the link matrix. The link matrix contains the pages each page points to. But what we want is to know which pages point to a given page, while retaining information about how many links each page contains (so store that in a separate array), as well as which pages contain no links at all (leaf nodes).
     @param outGoingLinks outGoingLinks[ii] contains the indices of pages pointed to by page ii @return a tuple of (incomingLinks, numOutGoingLinks, leafNodes) """
     nPages = len(outGoingLinks) # incomingLinks[ii] will contain the indices jj of the pages linking to page ii incomingLinks = [[] for ii in range(nPages)] # the number of links in each page numLinks = zeros(nPages, int32) # the indices of the leaf nodes leafNodes = []
     for ii in range(nPages):  if len(outGoingLinks[ii]) == 0:   leafNodes.append(ii)  else:   numLinks[ii] = len(outGoingLinks[ii])   # transpose the link matrix   for jj in outGoingLinks[ii]:    incomingLinks[jj].append(ii)  incomingLinks = [array(ii) for ii in incomingLinks] numLinks = array(numLinks) leafNodes = array(leafNodes)
     return incomingLinks, numLinks, leafNodes    
    def pageRank( linkMatrix = [[]],        alpha = 0.85,  convergence = 0.01,  checkSteps = 10        ): """ Convenience wrap for the link matrix transpose and the generator.
     @see pageRankGenerator for parameter description """ incomingLinks, numLinks, leafNodes = transposeLinkMatrix(linkMatrix)
            for gr in pageRankGenerator(incomingLinks, numLinks, leafNodes, alpha = alpha, convergence = convergence, checkSteps = checkSteps):                final = gr
            return final

  3. Jingjing Alice says:

    To 随风:python..不看后面,你就差点吓死我了…~你像病毒一样来我blog…
    To MW: 嗯。

  4. says:

    过去的让它过去就好

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